A small mass slides down an inclined plane of inclination θ with the horizontal. The co-efficient of friction is µ = µ 0 x where x is the distance through which the mass slides down and µ 0, a constant. Then find
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
v max = 
x = 
Sol. Acceleration of mass at distance x
a = g (sin θ – μ 0 x cos θ )
Speed is maximum, when a = 0
g (sin θ – μ 0 x cos θ ) = 0
x = 
for maximum speed
a = g (sin θ – μ 0 x cos θ )
= g (sin θ – μ 0 x cos θ )
vdv = (gsin θ – μ 0 gx cos θ ) dx
Integrating both sides
= 
= 
After Applying limits
v max = 
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